almost passes test but does not return array

04_removeFromArray/removeFromArray.js

@@ -1,83 +1,17 @@
-// Third iteration:
+// Almost passes test but doesn't return as array:
 
 const removeFromArray = function([a, ...b], c, ...d) { 
+
   let firstArray = [a, ...b];
   let secondArray = [c, ...d];
-  console.table(firstArray);
-  console.table(secondArray);
 
   let combinedArray = [...firstArray, ...secondArray];
-
-let removeDuplicates = [...new Set(combinedArray)]
-
-}
-
-removeFromArray(["a", "b", "c", "d"], "e", "f", "g")
-
-// Need to figure out how to turn second parameter into an array
-
-/*
-const removeFromArray = function([arrayOne], arrayTwo) { 
-
-  function f(a, ...arrayTwo) {
-    let newArray = [...arrayTwo];
-    console.table(newArray)
-    return newArray
-  }
-
-}
-*/ 
-
-
-// Second iteration that fails test but can remove duplicates from arrays:
-
-const removeFromArray = function([arrayOne], [arrayTwo]) {
-
-
-
-  let combinedArray = [...arrayOne, ...arrayTwo];
-
   let removeDuplicates = [...new Set(combinedArray)]
   
-  // console.table(removeDuplicates)
+  console.table(removeDuplicates)
+}
 
-};
-
-removeFromArray(["A", "B"], ["C", "D"])
-
-
-
-
-
-// First iteration that fails all tests but can create an array:
-
-/* const removeFromArray = function([array], args) {
-
-        function createArray(...args) {
-            let newArray = args
-      }
-
-        let oldArray = array;
-
-        let combinedArray = [...newArray, ...oldArray];
-
-        let removeDuplicates = [...new Set(combinedArray)]
-
-
-
-  };
-
-  */
-
-// NEXT need to find way to compare the two arrays
-// i.e. compare "array" and "args"
-// and check for duplicates..
-// and remove the duplicate from the first array
-// and finally return the new version of the first array
-// check for methods here: https://dev.to/soyleninjs/3-ways-to-remove-duplicates-in-an-array-in-javascript-259o
-
-
-// const removeFromArray = function() {};
+removeFromArray(["a", "b", "c", "d"], "d", "e", "f", "g")
 
 
 // Do not edit below this line