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solved removeFromArray exercises

This commit is contained in:
Salih 2020-07-16 01:15:36 +02:00
parent 18d7b040d6
commit 5b9ae18836
2 changed files with 9 additions and 8 deletions
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3
removeFromArray/removeFromArray.js
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@ -1,4 +1,5 @@
const removeFromArray = function() { const removeFromArray = function(array, ...args) {
return array.filter(item => !args.includes(item))
} }

12
removeFromArray/removeFromArray.spec.js
View File

@ -4,22 +4,22 @@ describe('removeFromArray', function() {
it('removes a single value', function() { it('removes a single value', function() {
expect(removeFromArray([1, 2, 3, 4], 3)).toEqual([1, 2, 4]); expect(removeFromArray([1, 2, 3, 4], 3)).toEqual([1, 2, 4]);
}); });
xit('removes multiple values', function() { it('removes multiple values', function() {
expect(removeFromArray([1, 2, 3, 4], 3, 2)).toEqual([1, 4]); expect(removeFromArray([1, 2, 3, 4], 3, 2)).toEqual([1, 4]);
}); });
xit('ignores non present values', function() { it('ignores non present values', function() {
expect(removeFromArray([1, 2, 3, 4], 7, "tacos")).toEqual([1, 2, 3, 4]); expect(removeFromArray([1, 2, 3, 4], 7, "tacos")).toEqual([1, 2, 3, 4]);
}); });
xit('ignores non present values, but still works', function() { it('ignores non present values, but still works', function() {
expect(removeFromArray([1, 2, 3, 4], 7, 2)).toEqual([1, 3, 4]); expect(removeFromArray([1, 2, 3, 4], 7, 2)).toEqual([1, 3, 4]);
}); });
xit('can remove all values', function() { it('can remove all values', function() {
expect(removeFromArray([1, 2, 3, 4], 1, 2, 3, 4)).toEqual([]); expect(removeFromArray([1, 2, 3, 4], 1, 2, 3, 4)).toEqual([]);
}); });
xit('works with strings', function() { it('works with strings', function() {
expect(removeFromArray(["hey", 2, 3, "ho"], "hey", 3)).toEqual([2, "ho"]); expect(removeFromArray(["hey", 2, 3, "ho"], "hey", 3)).toEqual([2, "ho"]);
}); });
xit('only removes same type', function() { it('only removes same type', function() {
expect(removeFromArray([1, 2, 3], "1", 3)).toEqual([1, 2]); expect(removeFromArray([1, 2, 3], "1", 3)).toEqual([1, 2]);
}); });
}); });