From e5b0c88297c92b5929313bb3284a0b19f79b145e Mon Sep 17 00:00:00 2001
From: ayer21 <98123280+ayer21@users.noreply.github.com>
Date: Fri, 22 Apr 2022 02:37:14 +0000
Subject: [PATCH] New simple solution proposed

this solution is based on two nested loops, one that takes an item from the first array, and one that checks if it's equal to a value in the second array, by looping through the second array.
it also uses the splice method to remove the item from the array. so no need to create a new one.
---
 removeFromArray/removeFromArray.js | 14 ++++++++++++++
 1 file changed, 14 insertions(+)

diff --git a/removeFromArray/removeFromArray.js b/removeFromArray/removeFromArray.js
index 3a68b8a..6b3b2fa 100644
--- a/removeFromArray/removeFromArray.js
+++ b/removeFromArray/removeFromArray.js
@@ -28,4 +28,18 @@ const removeFromArray = function (...args) {
 // }
 //
 
+// another solution is to loop through the first array items, and for each item, you check if it's on the second array. if true,
+// the item is removed from the array using splice() method.
+const removeFromArray = function (array, ...num) {
+    let i = 0;    // this will be a counter for loop iterations, it will be used as the array's index indicator
+    firstArray:
+    while (i < array.length) {
+        for (item of num) {
+            if (array[i] === item) { array.splice(i, 1); continue firstArray }
+        }
+        i++;
+    }
+    return array;
+};
+
 module.exports = removeFromArray;